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Natali [406]
2 years ago
6

Solve for x.

Mathematics
2 answers:
denis-greek [22]2 years ago
5 0

Answer:

\frac{3\±\sqrt{3}}{3}

Step-by-step explanation:

Whe have the function 3x^2-6x+2=0

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

\frac{-b\±\sqrt{b^2-4ac}}{2a}

Where:

a = 3

b = -6

c = 2

Then

\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}

finally the correct answer is  \frac{3\±\sqrt{3}}{3}

lisov135 [29]2 years ago
3 0

just made this so the other person could get brainiest as a thanks.

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-1/2=3/2k+3/2<br> explain how you got your answer
meriva

-1/2=3/2k+3/2


Rewrite the equation to have k on left side


3/2k+3/2=-1/2


Simplify 3/2k


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3k/3=-4/3


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