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2 years ago

Find the GCF of each pair of monominals 54gh,72g

Mathematics

1 answer:

wel2 years ago

7 0

18 is the answer I believe hopefully this is correct

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What is the probability of tossing two coins in Irvington bus land on heads?

d1i1m1o1n [39]

Sample space = {TT, HH, TH, HT} where T is tail and H is head.
Number of outcomes = 4
The probability of getting two heads on tossing two coins
$= (\frac{1}{4} \times 100)\% \\ = 25\%$

Answer:

D) 25%

Hope you could understand.

If you have any query, feel free to ask.

6 0

1 year ago

*30 POINTS* In a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. How many children had neither

Gnesinka [82]

Answer:

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

6 0

3 years ago

Read 2 more answers

2.24 Exit poll: Edison Research gathered exit poll results from several sources for the Wisconsin recall election of Scott Walke

iVinArrow [24]

Answer:

0.4929 = 49.29% probability that he voted in favor of Scott Walker

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Having a college degree.

Event B: Voting for Scott Walker.

They found that 57% of the respondents voted in favor of Scott Walker.

This means that $P(B) = 0.57$

Additionally, they estimated that of those who did vote in favor for Scott Walker, 33% had a college degree

This means that $P(A|B) = 0.33$

Probability of having a college degree.

33% of those who voted for Scott Walker(57%).

45% of those who voted against Scott Walker(100 - 57 = 43%). So

$P(A) = 0.33*0.57 + 0.45*0.43 = 0.3816$

What is the probability that he voted in favor of Scott Walker?

$P(B|A) = \frac{0.57*0.33}{0.3816} = 0.4929$

0.4929 = 49.29% probability that he voted in favor of Scott Walker

3 0

3 years ago

Can you please help?

Alborosie

Can’t help DDDD: bcoz link is a scam

7 0

2 years ago

81,27,9,__,__,__,__ fill in the blanks

Sever21 [200]

3, 1, 0.3333, 0.111111
I think

5 0

2 years ago