When triangles are similar, ratios of corresponding side lengths are the same. The side lengths you know are CD, DU, VW, WU. (You also know CU, but you do not know the corresponding length VU.)
The ratios can be formed in any convenient way, but it is already clear that the triangles are not similar. CD = 73 is a prime number, and neither DU nor VW is a multiple of that. For example, ...
... CD/VW = 73/84 ≠ 48/55 = DU/WU
Let the number of marbles be M,
then,
M=6a+4 (when shared among 6 students)
M=7b+4 (when shared among 7 students)
M=8a+4 (when shared among 8 students)
thus
M-4=6a
M-4=7b
M-4=8c
That is M-4 is the smallest number which is a multiple of 6, 7 and 8
Thus we need to find the LCM(6, 7, 8)
LCM(6, 7, 8)=LCM(2*3, 7, 2*2*2) = 2*2*2*3*7=8*21=168
The smallest M-4 is 168,
so the smallest M is 168+4=172
Answer: 172
Answer:
Step-by-step explanation:
Take the log of both sides:
log(2) = t*log 1.015, so that:
log(2)
t = --------------- = 46.6 compounding periods, which is 46.6/4, or 11.6 years
log 1.015
Can't write this exponential equation as a logarithm; instead, CAN write it in logarithmic form.
Answer:
D
Step-by-step explanation:
I am not 100 percent sure.
