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<h2>The specific heat of the metal is 0.274951 calories/gram-degree C.</h2>Step-by-step explanation:
Let, the specific heat of the container is x calories/gram-degree C.
The container and water gains (18 - 15) = 3 degrees C.
Hence, the transfer of heat is .
The metal, which is dropped in the water, losses (164 - 18)= 144 degrees C.
Hence, the transfer of heat is .
As per the given conditions,
.