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marshall27 [118]
2 years ago
10

If demand function is Qd=150+10p and supply function is Qs=300-2p, find the equilibrium price.​

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
8 0

Answer:

qd = qs

150+10p=300-2p

10p+2p=300-150

Step-by-step explanation:

12p=150

P=150÷12

P=12.5

The equilibrium price is 12.5 or 13

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I don't get this pls help
dmitriy555 [2]

Answer:

  d, e

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

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In this case, it means the product is ...

  (6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

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The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

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Only the last two choices, d and e, apply.

3 0
3 years ago
I need hard and easy math questions with the answer, i need 10 questions<br><br>thnx
nydimaria [60]

Answer:

https://www.khanacademy.org/

Step-by-step explanation:

I am not entirely sure what you mean however if you sign up for this website and go to whichever grade level you need you can practice all you want

8 0
1 year ago
I need help with this question plzz
Serjik [45]

Answer:

40 miles away from home

To put it in yard would be 82,720

Step-by-step explanation:

8 0
3 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
3 years ago
A bicycle tire has a radius of 13 1/4 inches. How far will the bicycle travel in 40 rotations of the tire? Round to the nearest
Sergeu [11.5K]

Answer:

the bicycle will travel 277.5 feet or 3,330.1 inches.

Step-by-step explanation:

the circumference(distance around a tire) is calculated by multiplying a circles diameter by pi. the diameter is twice the length of the radius.

so if you multiply 13 1/4 by 2 you get 26 1.5 if you multiply that by pi than you get the circumference. then multiply this by 40 to get the inches traveled and divide that by 12 to get the number of feet traveled.

8 0
3 years ago
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