For lines to be perpendicular their slopes have to be negative reciprocals of one another, mathematically...
m1*m2=-1...in this case:
y=5x/3=1/3 so the slope of the lines is 5/3 so any line that has a slope of:
5m/3=-1,
m=-3/5 is perpendicular to the original line...
If i am correct, these values should add to 360, so I do it by
140 + 110 + 62 = 312
360 - 312 = 48
So the value of the last side must equal 48.
Your answer would be x = -9. Proof:
If 9 is filled in, you would have
(3 - 5(-9))
(3 - (-45))
48
Then
48 + 140 + 110 + 62 = 360!
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➷ M = k x r^2
Substitute in the values:
14 = k x 2^2
Divide both sides by 2^2 to find k:
k = 3.5
Substitute the new values in:
224 = 3.5 x r^2
Divide both sides by 3.5 to find r^2
r^2 = 64
Square root it:
r = 8
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Answer:
Slope is 0
Equation is y=120
Step-by-step explanation:
the slope is 0 since there is only one output value
And if there was only one input value the slope would be undefined
Hopes this helps
Let us say that,
<span>A = perimeter of football field of the 1st
school</span>
B = perimeter of football field of the 2nd school
C = perimeter of football field of the 3rd school
So that:
A = 320 m
B = 360 m
C = 400 m
So the first thing we have to do to find for the minimum
laps to make is to divide every perimeter by the smallest one, therefore divide
all by 320 m, hence:
A’ = 1
B’ = 1.125
C’ = 1.25
Now multiply everything by a number such that all laps
will be a whole number, in this case multiply everything by 8:
A’ = 8
B’ = 9
C’ = 10
Hence the laps to run are:
<span>8, 9 and 10</span>
