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gogolik [260]
3 years ago
5

If line b is perpendicular to line a, and line c is

Mathematics
1 answer:
Nikolay [14]3 years ago
8 0

Answer:

y=x-2.5

Step-by-step explanation:

If it is perpendicular to a, just like b, it has the same slope, but, it has a y-intercept of 2.5, unlike b, which has a y-intercept of 1

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Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
Which is the equation of the given line in slope-intercept form? y= -1/4 x +1 y= -4x+1 y=4x-1 y=4x=+1
sergejj [24]

Answer:

y = -4x + 1

Step-by-step explanation:

Slope intercept form is y = mx + b.

The slope can be found by using the formula (y2-y1)/(x2-x1)

So (5-(-3))/(-1-1) which equals 8/-2 which can be simplified to -4.

Also this problem only has one answer with a slope of -4.

8 0
3 years ago
Id get this question can u help me ?
DedPeter [7]

The answer is this I’m sorry :)) I hope this helped

8 0
4 years ago
A train travels 120 miles in 1.5 hours. At this rate how far will the train travel in 6 hours
levacccp [35]
480 miles in 6 hours
8 0
4 years ago
Read 2 more answers
Square root of 144 X^7 Y^5
LekaFEV [45]
The first step to solving this is to factor out the first perfect square
\sqrt{12^{2} x^{7} y^{5}   }
now factor out the second perfect square
\sqrt{ 12^{2} x^{6} X x  y^{5}  }
then factor out the second perfect square 
\sqrt{ 12^{2}  x^{6} X x  y^{4} X y}
the root of a product is equal to the product of the roots of each factor
\sqrt{ 12^{2} } \sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the first square root
12\sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the second square root
12x³\sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the third square root
12x³y²\sqrt{xy}
this means that the correct answer to your question is 12x³y²\sqrt{xy} .
let me know if you have any further questions
:)
4 0
3 years ago
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