Question

Write the standard form of the equation that is parallel to y = -6x + 5 and goes through point (4, 4).

Answer 1

6x + y = 28.  The standard form of the equation that is parallel to y = -6x + 5 and goes through point (4, 4) is 6x + y = 28.

The equation is written in the slope-intercept form y = mx +b. So:

y = -6x + 5

The slope m = -6

Since the slopes of parallel lines are the same, we are looking for a slope line m = -6 and goes through point (4, 4).

With the slope-intercept form:

y = mx + b

Introducing the slope m = -6:

y = -6x + b

Introducing the point (4, 4):

4 = -6(4) + b

b = 4 + 6(4)

b= 24 + 4

b = 28

Then

y = -6x + 28

write the equation in standard form ax + by = c:

y = -6x + 28

6x + y = 28