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sergejj [24]
3 years ago
9

Which of these activities is not related to the muscular system?

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0
Maybe A, please correct me if I’m wrong
leonid [27]3 years ago
5 0
A is the answer.... have a good day
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Part A: Factor x2b2 − xb2 − 6b2. Show your work. (4 points)
IrinaVladis [17]
PART A. Notice that we have b^{2} as a common factor in all the terms, so lets factor that out:
x^{2} b^2-xb^2-6b^2
b^2(x^{2} -x-6)
Now we need can factor x^{2} -x-6:
b^2(x^{2} -x-6)
b^2(x+2)(x-3)

We can conclude that the complete factorization of x^{2} b^2-xb^2-6b^2 is b^2(x+2)(x-3).

PART 2. Here we just have a quadratic expression of the form a x^{2} +bx+c. To factor it, we are going to find <span>two numbers that will multiply to be equal the </span>c<span>, and will also add up to equal </span><span>b. Those numbers are 2 and 2:
</span>x^{2} +4x+4=(x+2)(x+2)
Since both factors are equal, we can factor the expression even more:
x^{2} +4x+4=(x+2)^2

We can conclude that the complete factorization of x^{2} +4x+4 is (x+2)^2.

PART C. Here we have a difference of squares. Notice that 4, can be written as 2^2, so we can rewrite our expression:
x^2-4=x^2-2^2
Now we can factor our difference of squares like follows:
x^{2} -2^2=(x+2)(x-2)

We can conclude that the complete factorization of x^2-4 is (x+2)(x-2)
7 0
3 years ago
HELP WILL GIVE BRANLIEST!
o-na [289]

Answer:

Step-by-step explanation:

7 0
3 years ago
Joey drives his car 80 miles per hour on the highway. Write an equation that relates his distance traveled. (d) to the time elap
marta [7]

Answer:

d=80+t? hope that helps not much info in this

Step-by-step explanation:

3 0
2 years ago
Please help asap!<br><br>the problem is in the picture
ladessa [460]

Given:

AB=6\ BC=r,\ CD=r,\ AD=12.

To find:

The value of r.

Solution:

We have,

AB=6\ BC=r,\ CD=r,\ AD=12.

We know that the radius is perpendicular to the tangent at the point of tangency

AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., m\angle D=90^\circ.

Using Pythagoras theorem, we get

AC^2=AD^2+CD^2

(6+r)^2=12^2+r^2

36+12r+r^2=144+r^2

12r=144+r^2-36-r^2

On further simplification, we get

12r=108

r=\dfrac{108}{12}

r=9

Therefore, the value of r is 9.

8 0
3 years ago
Evaluate the function for x = –2a, if a = 3.
Snezhnost [94]
The answer that you should get is A
8 0
3 years ago
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