Four less than twice a number is ten. Find the number

12 + 30x<br><br> neeeeeeeeed heeeeeeeeeeeelp

deff fn [24]

Answer:42x

Step-by-step explanation:

4 0

3 years ago

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4. A<br> is an algebraic expression made by<br> adding or subtracting terms.

Rasek [7]

Answer:

You have one algebraic expression. It can be simplified by adding and subtracting like terms within it.

You have two algebraic expressions and are asked to add or subtract them. After adding or subtracting, you’ll end with one final algebraic expression.

4 0

3 years ago

Please help!!!! Ik this is easy but I cant think correctly rn

olasank [31]

Answer:

Lol i get like that too. This is 10

Step-by-step explanation:

4+5=9

1/2+1/2=1

9+1=10

6 0

3 years ago

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Alex earns $7.50 per hour at his part-time job. Last week he worked 15 hours. This week he worked 21 hours. What is the total am

masha68 [24]

Answer:$270

Step-by-step explanation:

Alex earns 7.50 per hour he worked 15 hours last week and 21 this week so 15+21=36 and since it is 7.50 per hour you multiply that and get $270

3 0

2 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

madreJ [45]

Answer:

a) There is a 1.82% probability of selecting a jury of all students.

b) There is a 0.02% probability of selecting a jury of all faculty.

c) There is a 36.4% probability of selecting a jury of three students and three faculty.

Step-by-step explanation:

6 individuals are going to be selected. There are no replacements.So:

(a) What is the probability of selecting a jury of all students?

Initially, there are 9 students and 15 people in the pool.

So, the probability that the first person selected to the jury is a student is $\frac{9}{15}$ .

Now, there are 8 students and 14 people in the pool. So, the probability that the second person selected to the pool is a student is $\frac{8}{14}$ .

We do this for the other four positions of the jury, and we end up with the following probability.

$P = \frac{9}{15}*\frac{8}{14}*\frac{7}{13}*\frac{6}{12}*\frac{5}{11}*\frac{4}{10} = 0.0182$

There is a 1.82% probability of selecting a jury of all students.

(b) What is the probability of selecting a jury of all faculty?

The same logic as a) above.

Initially, there are 6 faculty and 15 people in the pool.

So, the probability that the first person selected to the jury is a faculty is $\frac{6}{15}$ .

Now, there are 5 faculty and 14 people in the pool. So, the probability that the second person selected to the pool is a faculty is $\frac{5}{14}$ .

We do this for the other four positions of the jury, and we end up with the following probability.

$P = \frac{6}{15}*\frac{5}{14}*\frac{4}{13}*\frac{3}{12}*\frac{2}{11}*\frac{1}{10} = 0.0002$

There is a 0.02% probability of selecting a jury of all faculty.

(c) What is the probability of selecting a jury of three students and three faculty?

I am going to initially find the probability of finding the following sequence:

J-J-J-F-F-F.

Initially, there are 9 students, 6 faculty, that is 15 people in the pool.

So, the probability that the first person selected to the jury is a student is $\frac{9}{15}$ .

Now, there are 8 students and 14 people in the pool. So, the probability that the second person selected to the pool is a student is $\frac{8}{14}$ .

Now, there are 7 students and 13 people in the pool. So, the probability that the third person selected to the pool is a student is $\frac{7}{13}$ .

Now, there are 6 faculty and 12 people in the pool. So, the probability that the third person selected to the pool is a faculty is $\frac{6}{12}$ .

Now, there are 5 faculty and 11 people in the pool. So, the probability that the third person selected to the pool is a faculty is $\frac{5}{11}$ .

Now, there are 4 faculty and 10 people in the pool. So, the probability that the third person selected to the pool is a faculty is $\frac{4}{10}$ .

So, the probability of getting just this sequence is

$P = \frac{9}{15}*\frac{8}{14}*\frac{7}{13}*\frac{6}{12}*\frac{5}{11}*\frac{4}{10} = 0.0182$

However, any combination with 3 students and 3 faculty is valid, no matter the order. So, we need to multiply P by the combination of 6, with 3 by 3. So

$P = 0.0182*C^{6}_{3,3} = 0.0182*\frac{6!}{(6-3)!3!} = 0.0182*\frac{6!}{3!}{3!} = 0.364$

There is a 36.4% probability of selecting a jury of three students and three faculty.

3 0

3 years ago