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irga5000 [103]
3 years ago
8

What is the partial products for 28×43

Mathematics
1 answer:
Schach [20]3 years ago
4 0
It is 28×43≈1204 that is the answer
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Anyone know the answer?
larisa86 [58]

Answer: D

Step-by-step explanation:

The loan requires no down payment, so it wont affect it even if you do pay for it.

3 0
3 years ago
Help me with this please!!!!
spayn [35]

Answer:

y = 2

Step-by-step explanation:

since on a horizontal line which means y axis and the sllope line is on 2

5 0
2 years ago
Please help me fast!!!. Joe and his family are touring Chicago. They want to visit the Willis Tower, hang out at Navy Pier, and
Nikolay [14]

Answer:

11:10 am.

Step-by-step explanation:

The first thing I'm going to do is to add all the given time together

Total time = time spent at Willis tower + time spent at Navy Pier + time spent shopping

Total time = 1 HR and 10 minutes + 3 HR and 10 minutes + 1 hour and 15 minutes

Total time = (1 + 3 + 1) hr + (10 + 10 + 15) minutes

Total time = 5 hours + 35 minutes

The question doesn't make mention of how long they spent making the journey so, I'm assuming they spent 35 minutes driving around from Willis to the Pier and finally while shopping

Time = total time + time spent driving

Time = 5 hours 35 minutes + 35 minutes

Time = 6 hours and 10 minutes

Now, this time we've calculated, is what we're going to subtract from the dinner time to get our final answer

Needed time = dinner time - time

Needed time = 5:10 pm - 6:10

Needed time = 17:10 - 6:10

Needed time = 11:10

This means that they ought to start their tour by 11:10 am, so that they can meet their dinner

7 0
3 years ago
Find the slope of the line passing through the points
frutty [35]

Answer:

Slope (m)= 0

Step-by-step explanation:

There is no slope due to a vertical line

x= 7

5 0
3 years ago
Read 2 more answers
What are the solutions if the equation x^2+4x+4=25
tatiyna

\text{Use}\ (a+b)^2=a^2+2ab+b^2\\\\x^2+4x+4=25\\\\x^2+2(2)(x)+2^2=25\\\\(x+2)^2=25\iff x+2=\pm\sqrt{25}\\\\x+2=-5\ \vee\ x+2=5\qquad\text{subtract 2 from both sides}\\\\\boxed{x=-7\ \vee\ x=3}


Other method:

x^2+4x+4=25\qquad\text{subtracr 25 from both sides}\\\\x^2+4x-21=0\\\\x^2+7x-3x-21=0\\\\x(x+7)-3(x+7)=0\\\\(x+7)(x-3)=0\iff x+7=0\ \vee\ x-3=0\\\\x+7=0\qquad\text{subtract 7 from both sides}\\\boxed{x=-7}\\\\x-3=0\qquad\text{add 3 to both sides}\\\boxed{x=3}

5 0
4 years ago
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