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laila [671]
3 years ago
6

Solve the following system of equations. Enter the x-coordinate of the solution. Round your answer to the nearest tenth.

Mathematics
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

x = 5.7 and y = 3.8

Step-by-step explanation:

We have given a system of equation.

5x+2y = 21                                    eq(1)

-2x+6y = -34                                 eq(2)

We have to find the solution of the given system.

Multiplying eq(1) by 3 , we have

15x+6y = 63

Subtracting above equation from eq(2), we have

15x+6y - (-2x+6y) = 63-(-34)

15x+6y+2x-6y = 63+34

17x+0 = 97

17x = 97

x = 97/17

x = 5.706≅5.7

Putting the value of x in eq(1) , we have

5(5.706)+2y = 21

2y = 21-28.53

2y = 7.53

y = 7.53/2

y = 3.765

We have to round it to the nearest tenth

y = 3.8

Hence, the solution of given system is x = 5.7 and y = 3.8

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4 0
3 years ago
This problem has been solved!
rjkz [21]

Answer:

1. Precise

2.Both

3.Precise

5.Neither

Step-by-step explanation:

Accuracy is the closeness of a measured value to a standard value.

Precision is the closeness of two or more measurements to each other.

1.The norm is 45 sit-ups in a minute.The students did, 64, 69,65 and 67. Values are not accurate compared to standard value 45.

Values are precise

Answer--Precise

2. Average score is 89.5

  Scores are 89,93,91,87

  Values are precise i.e a difference of 2 from each score

  Values are accurate because the average score is 90 thus compared to      the known average score of 89.5 they are accurate.

Answer-Both

3. Yesterday temperature=89

   Tomorrow=88

    Next day=90

   Average =75

   Values are precise i.e. difference of ± 1°

   Values are not accurate compared to the average temperatures of 75 F

   Answer---Precise

5. The jar contained 568 pennies

   The 6 people guessed the numbers as

    735,209,390,300,1005, 689

  The values are not precise

  The values are not accurate

  Answer---Neither

5 0
3 years ago
15 points: can someone help me with this thank you. (all separate equations)
OLga [1]

Step-by-step explanation:

6x+3y=12\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\6x-6x+3y=12-6x\\\\3y=12-6x\qquad\text{divide both sides by 3}\\\\\dfrac{3y}{3}=\dfrac{12}{3}-\dfrac{6y}{3}\\\\\large\boxed{y=4-2y}\\\\===================

2p-k=3\qquad\text{subtract}\ 2p\ \text{from both sides}\\\\2p-2p-k=3-2p\\\\-k=3-2p\qquad\text{change the signs}\\\\k=-3+2p\\\\\large\boxed{k=2p-3}\\\\===================

6v-2w=10\qquad\text{subtract}\ 6v\ \text{from both sides}\\\\6v-6v-2w=10\\\\-2w=10-6v\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2w}{-2}=\dfrac{10}{-2}-\dfrac{6v}{-2}\\\\w=-5+3v\\\\\large\boxed{w=3v-5}\\\\===================

5 0
3 years ago
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