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aleksandrvk [35]
3 years ago
11

Write a function rule for the table. x0123f(x) 3456

Mathematics
1 answer:
crimeas [40]3 years ago
3 0
Y = x +3

Is your answer!
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Please someone help!!!​
kari74 [83]

Answer:

0.001189 x 10^7

Step-by-step explanation:

4.1 x 10^7 gallons of water

2,900 gallons of water = 2.9 x 10^3

Balance the 10th power with the first one.

2,900 = 0.00029 x 10^7

Multiply only the decimal number...

4.1 x 0.00029 = 0.001189

The answer is...

0.001189 x 10^7

6 0
3 years ago
Which expression is equivalent to (5x + 2) + (4x - 3)?
mamaluj [8]
The answer to this is E
7 0
3 years ago
Which expression is equivalent to 7a^2b + 10a^2b^2 + 14a^2b^3?
vladimir1956 [14]
7a^2b + 10a^2b^2 + 14a^2b^3 =
a^2b (7 + 10b + 14b^2) <==
3 0
4 years ago
Read 2 more answers
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
4 years ago
Find the value of x in the isosceles triangle​
Ne4ueva [31]

Answer:

10

Step-by-step explanation:

Seeing the 5 12 13 triple you get 1/2x=5 so

x=10

4 0
3 years ago
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