Answer:
C, E
Step-by-step explanation:
Here, we want to change the equation of a circle from general form to standard form. This is done by making the leading coefficients 1, completing the squares, and then rewriting the equation in standard form.
The leading coefficients of the given equation are 2, so we first want to divide by 2. This gives ...
x² +y² -4x -6y +8 = 0
Subtracting 8 puts us in better position to complete the squares.
x² +y² -4x -6y = -8
Now, we can add the squares of half the coefficients of the linear terms.
(x² -4x +4) +(y² -6x +9) = -8 +13 . . . . . . matches C
And we can simplify this to the standard form equation:
(x -2)² +(y -3)² = 5 . . . . . matches E
Answer:
Hope this solution helps you
Answer:
25
Step-by-step explanation:
The graph of

is shown in the graph below.
The graph is of ∩-shape when the constant

of the quadratic equation

is negative
Answer:
There are many. Two examples are

Step-by-step explanation:
There are many examples. The simplest is
1 -

It is trivial that

2 -

That function is injective as well.

An example of a function that is NOT injective is

Notice that
