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stealth61 [152]
3 years ago
14

F(x) -7 x<= -3 ax-b -3 8 x>= 3

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
HshshsnhsNnsndnxnx. Xbbsjd
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Complete the statements to find the measurements of Za and Zb.
Sunny_sXe [5.5K]
What do you want me to find
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3 years ago
A random sample of 2 measurements is taken from the following population of values: 0, 1, 3, 4, 7. What is the probability that
mafiozo [28]

Answer:

1/5

Step-by-step explanation:

Range as a measure of central tendency is the difference between the highest value and the lowest value in a given set of data.

Given the samples 0,1,3,4,7

Total number of samples is 5

The range is gotten by taking the difference of 2 samplesout of 5samples and this can be done in 5C2 ways.

5C2 = 5!/(5-2)!2!

= 5!/3!2!

= 5×4×3!/3!×2

= 10ways

The total outcome is therefore 10

To get the probability that the range is 4, we need to get the required outcome of getting range of 4 and this can only occur twice

The range can be gotten by taking the difference between 7 and 3, it can also be gotten by taking the difference between 4 and 0. Both differences will give us a total of 4

The expected outcome is therefore 2

the probability that the range of the sample is 4 = expected outcome/total outcome

= 2/10

= 1/5

7 0
3 years ago
gail works for a vending company. she gets paid $64 per week plus 20% of her total salesm how much will her total sales for the
denis23 [38]
At least 680 in sales because 200$-64$ is 136. 136*5=680 because 136 is one fifth or 20% of 680
4 0
3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
3 years ago
Find the circumference of the circle. PLEASE HELP I HAVE 5 MINUTES LEFT :(
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Answer:

18.84

Step-by-step explanation:

5 0
3 years ago
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