Answer:
It is given that the weight of the person is 102 N
We have the force that shall be needed to being the man out in minimum amount of time shall correspond to the maximum tension that can be developed
Thus using Newton's second law we obtain the acceleration that the man shall attain
Now using second equation of kinematics to obtain time 't' we get
Answer:
Kinetic energy of mass A = 20 J
Kinetic energy of mass B = 40 J
Explanation:
Lets take final speed of mass A = v
The final speed of mass B = v'
mass of A= m
mass of B = m'
m = 2 m'
There is no any external force so the linear momentum will be conserve.
Pi = pf
0 = m v + m ' v'
0 = 2 m ' v +m ' v'
v ' = - 2 v
Now from energy conservation
1/2 k x²=1/2 m v² + 1/2 m' v'²
60 = 1/2 m v² + 1/2 m' v'²
m v² + m' v'² = 120
2 m ' (-v'/2)² + m' v'² = 120
m ' v'²/2 + m' v'² = 120
m' v '² = 80
m =2 m' and v ' = - 2 v
So
m/2 ( 4 v²) = 80
m v ²=40
So the kinetic energy of mass A= 1/2 m v² = 20 J
Kinetic energy of mass B = 1/2 m' v'² = 40 J
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Answer:
The periodic table illustrate some of the elements from Hydrogen to Calcium
I'd go for b) v squared.
Wind is air in motion. So, it has kinetic energy. For a given mass of air at a certain speed, the kinetic energy would be (1/2)mv^2.
Since everything else in the chain seems to be proportional, then it's the v^2 bit that seems to be important. Hence the answer I post here.
