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Maslowich
2 years ago
12

12) A horizontal force of 200 N is applied to move a 55-kg cart (initially at rest) across a 10 m level surface. What is the fin

al speed of the cart? [hint: use work – energy principle] [3 marks]
Physics
1 answer:
WINSTONCH [101]2 years ago
3 0

Hi there!

We can use the following:

W = ΔKE = F · d

Find the work done on the cart:

W = 200 · 10 = 2000 J

Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:

2000J = KEf - KEi

KE is given as:

KE = \frac{1}{2}mv^2

2000J = 1/2(55)v²

4000 = 55v²

√(4000/55) = 8.53 m/s

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