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seropon [69]
3 years ago
9

At a sudden contraction in a pipe the diameter changes fromD1toD2. The pressure drop,Δp, which develops across the contraction i

s a function ofD1andD2, as well as the velocity,V, in the larger pipe, and the fluid density, rho, and viscosity,μ. UseD1,V, andμas repeating variables to determine a suitable set of dimensionless parameters. Why would it be incorrect to include the velocity in the smaller pipe as an additional variable?

Physics
1 answer:
Sever21 [200]3 years ago
5 0

Answer: The working and answer can be viewed from the screenshots below. Thanks

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5 N acting in the same direction as the 10 N force

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4. O/N 15/P11/Q11
anygoal [31]

Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

P = F/A

It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

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0.30(0.50) = 0.15 m²

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The pressure when the face with the largest area (0.20 m²) is down is

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the other possible pressures would be

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3 years ago
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Answer:

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V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

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(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

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2 years ago
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Explanation:

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