Question

An airplane traveling at 60 m/s comes to a stop in 10 seconds. Calculate the airplane’s acceleration. Show the appropriate formula and show your work with units in order to receive credit. (Chapter 2 – Pages 57-58)

Answer 1

Answer:

-6m/s^2

Explanation:

Acceleration is the quantity that increase or decrease the velocity per time unit, that means, we can obtain that quantity by dividing change in velocity between time, in this case a=(Vfinal-Vinitial)/t, replacing a=(0m/s-60m/s)/10s , so a=-6m/s^2.

Answer 2

An airplane traveling at 60 m/s comes to a stop in 10 seconds. The airplane’s acceleration is - 6 m / s^{2}[/tex]

Answer: - 6 m / s^{2}[/tex]

Explanation:

Given that the air plane was travelling at the speed of 60 m/s and the time taken to came to rest was 10 sec. Therefore, the acceleration can be calculated by following method,  

Given that velocity = 60 m /s

Time taken to stop t = 10 sec

We can thus know that the final velocity is zero as the air-plane comes to rest, so the given velocity is the initial velocity

Therefore, acceleration or rather in this case,

      $\text { deceleration }=\frac{v-u}{t}$

      $a=\frac{60-0}{10}= - 6 m / s^{2}$