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Goryan [66]
3 years ago
10

The sum of two numbers is 36. Twice the first number minus the second is 6. Find the numbers.

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Hey there!!

Let's take the two numbers as 'x' and 'y'

The sum of these two numbers is 36.

... x + y = 36

Twice the first number minus the second is 6.

... 2x - y = 6

Now, we have two equations.

_______________________________________________________

... x + y = 36  

... 2x - y = 6

Now, let's add both the equations.

... 3x = 42

Divide each side by 3.

... x = 42 / 3

... x = 14

<em>Hence, the first number is'14'. </em>

We know the sum of both the numbers is 36.

... x + y = 36

... 14 + y = 36

Subtract 14 on both sides.

... y = 36-14

... y = 22

<em>Hence, the second number is 22. </em>

<em>The numbers are 14 and 22. </em>

Hope my answer helps!!

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x = -16  

Plug -7 into both equations and you will see that it is a solution

\frac{x}{4} + 1 = -3

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Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
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5 0
3 years ago
Your cell phone company Offers you a choice between two promotional deals you can either get 500 free text messages with the cha
ollegr [7]

Answer:

The number of messages that will cost same both plans is <u>1000</u>.

Step-by-step explanation:

Given,

For 1st offer:

Total number of messages = 500

Charge of each message after 500 messages = $0.10

For 2nd offer:

Total number of messages = 400

Charge of each message after 400 messages = $0.20

We need to find out the number of messages can be sent for equal cost of both plans.

Solution,

Let the number of messages be 'm'.

So For 1st offer:

Total cost 'c' is equal to fixed cost for 500 messages plus charge of each message multiplied with number of messages.

framing in equation form, we get;

c=500+0.10m

Again for 2nd offer:

Total cost 'c' is equal to fixed cost for 400 messages plus charge of each message multiplied with number of messages.

framing in equation form, we get;

c=400+0.20m

Now the question said that the charge would be the same.

So we can say that;

500+0.10m=400+0.20m

On combining the like terms, we get;

500-400=0.20m-0.10m\\\\100=0.1m\\\\

Now using multiplication property, we will multiply both side by '10' and get;

100\times 10=0.1m\times10\\\\1000=m

Hence The number of messages that will cost same both plans is <u>1000</u>.

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