All categories

3 years ago

The sum of two numbers is 36. Twice the first number minus the second is 6. Find the numbers.

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

Hey there!!

Let's take the two numbers as 'x' and 'y'

The sum of these two numbers is 36.

... x + y = 36

Twice the first number minus the second is 6.

... 2x - y = 6

Now, we have two equations.

_______________________________________________________

... x + y = 36

... 2x - y = 6

Now, let's add both the equations.

... 3x = 42

Divide each side by 3.

... x = 42 / 3

... x = 14

Hence, the first number is'14'.

We know the sum of both the numbers is 36.

... x + y = 36

... 14 + y = 36

Subtract 14 on both sides.

... y = 36-14

... y = 22

Hence, the second number is 22.

The numbers are 14 and 22.

Hope my answer helps!!

You might be interested in

How do you prove the two triangles congruent?

bazaltina [42]

5 ideas
1.SSS (side, side, side) SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. ...
2.SAS (side, angle, side) ...
3.ASA (angle, side, angle) ...
4.AAS (angle, angle, side) ...
5.HL (hypotenuse, leg)

3 0

3 years ago

What graph represents the equation y=1.4x+2

Goryan [66]

Hope this helps you.

7 0

3 years ago

List the next four multiples of the unit fraction 1/5,

svetoff [14.1K]

Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1

Hope this helps.. :)

6 0

3 years ago

I need the answer please

devlian [24]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: x = 37

Explanation:

2x-5 + 3x = 180

5x - 5 = 180

5x = 185

x = 37

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

5 0

2 years ago

Read 2 more answers

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago