1.17×6×1023
Wich equals 7.02×1023
Your final answer is 7.02×1023
Answer:
Percent yield = 79.79 %
Explanation:
Given data:
Mass of Al₂O₃ = 821 g
Mass of Al = 349 g
Percent yield = ?
Solution:
Chemical equation:
2Al₂O₃ + 3C → 4Al + 3CO₂
Number of moles of Al₂O₃:
Number of moles = mass/molar mass
Number of moles = 821 g/ 101.96 g/mol
Number of moles = 8.1 mol
Now we will compare the moles of Al with Al₂O₃.
Al₂O₃ : Al
2 : 4
8.1 : 4/2×8.1 = 16.2 mol
Mass of Al:
Mass = number of moles × molar mass
Mass = 16.2 mol × 27 g/mol
Mass = 437.4 g
Percent yield:
Percent yield = (actual yield / theoretical yield)× 100
Percent yield = (349 g/ 437.4 g) × 100
Percent yield = 79.79 %
A goes with u, C with G, and T with A
For sodium, it has 1 valence electron
For oxygen, it has 6 valence electrons
For iron, it has 2 valence electrons
Answer:
6.5
Explanation:
No of moles is the ratio of reacting mass to molar mass
RM - 270.4g
MM - 23+16+1= 40g/mol
270.4/40= 6.76mol
