I think the answer to ur problem is 4 my hitta
Answer:
3.586 mol of H2O (correct to 4 sig figs)
Explanation:
Known: 64.60 g water (a.k.a. H2O)
1 mol of H2O = 18.015g
How did I get that mass? Looking at the periodic table and adding atomic mass of 2 hydrogens + 1 oxygen ( 2(1.008) +15.999) = 18.015g
How many of mol of H2O will form?
Solving for the unknown:
64.60g • (1 mol H2O / 18.015g H2O) = 3.58590 mol H2O
Answer:
0.74 g O
3
=
48
0.74
=0.0154 mol O
3
0.67 g NO=
30
0.67
=0.0223 mol NO
O
3
is the limiting reagent and NO is in excess =0.0223−0.0154=0.007 mol
Thus, O
3
taken =NO
2
formed =0.0154 mol NO
2
=0.0154×46 g NO
2
Explanation: