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Using the mass/volume percentage method for percentages of the solution, you simply divide the grams of solute by the volume of the solution and multiply by 100 to get your percentage.
(75.0g/250mL)•100 = 30.0% solute
Answer:
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Answer:
A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:
C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol
The value given for ΔH∘rxnΔHrxn∘ means that:
a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.
b. the reaction is endothermic.
c. the enthalpy of formation of propane is 2202 kJ/mol.
d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.
e. None of these.
Answer:
Check the explanation
Explanation:
Glycolysis is the process in the field of chemistry in which a specific glucose molecule is broken down to become two or more molecules of pyruvic acid or pyruvate. The process and procedure is a metabolic multi-step pathway that happens in the cytoplasm of plant cells, animal cells, and the cells of various microorganisms.
The answer to the question above is:
1) nonspontaneous because deltaG is positive
2) glucose + ATP --> glucose-6-phosphate + ADP
3) -16.7 kJ/mol
4) yes, because deltaG is negative
