Answer:
The solubility is 
Explanation:
From the question we are told that
The volume of the solution is 
The initial temperature is 
The final temperature is 
The additional precipitate is 
Yes because the solubility of the substance X is the amount of X needed to saturate a unit volume of the solvent (for solubility of a solute to be calculated the solute must be able to saturate the solvent)
now we see that the substance X saturated the solvent because a precipitate was formed which the student threw away
The solubility at 21 ° C is mathematically represented as
Mass of water(
) in the solution is mathematically represented as
Where 
So
So
Solar power is extremely expensive and can be even more expensive to maintain.
Zinc would be considered the strongest reducing agent.
<h3>Reducing agent</h3>
A reducing agent is a chemical species that "donates" one electron to another chemical species in chemistry (called the oxidizing agent, oxidant, oxidizer, or electron acceptor). Earth metals, formic acid, oxalic acid, and sulfite compounds are a few examples of common reducing agents.
Reducers have excess electrons (i.e., they are already reduced) in their pre-reaction states, whereas oxidizers do not. Usually, a reducing agent is in one of the lowest oxidation states it can be in. The oxidation state of the oxidizer drops while the oxidizer's oxidation state, which measures the amount of electron loss, increases. The agent in a redox process whose oxidation state rises, which "loses/donates electrons," which "oxidizes," and which "reduces" is known as the reducer or reducing agent.
Learn more about reducing agent here:
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<h3 />
Answer:
NADH and FADH
Explanation:
An oxidizing agent is a chemical substance which has one among the three listed properties.
1. It can accept electrons.
2. It can remove hydrogen.
3. It can add oxygen to the reactant.
NAD+ and FAD+ serve as an oxidizing agent because they not only accept a pair of electron but also remove hydrogen. In this molecule, they have actually taken hydrogen from carbon where OH functional group was present and oxidizing that particular alcohol group to ketone. Please see the image attached.
Answer:
for question no. 1 OPTION b is correct
