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castortr0y [4]
3 years ago
5

The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The b

all is 50 meters from the ground after about how many seconds
2.45
3.16
5.48
7.07
Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

Third option: 5.48

Step-by-step explanation:

Given the quadratic  model that represents the approximate height in meters of the ball f(x)=-5x^2 +200. the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting f(x)=50 and solving for x.

Then:

50=-5x^2 +200

Subtract 200 from both sides:

-200+50=-5x^2 +200-200\\-150=-5x^2

Divide both sides by -5:

\frac{-150}{-5}=\frac{-5x^2}{-5}\\30=x^2

Apply square root to both sides:

\sqrt{30}=\sqrt{x^2}\\\sqrt{30}=x\\5.48=x

The ball is 50 meters from the ground after about 5.48 seconds.

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Answer: 13 hours and 15 minutes

Step-by-step explanation:

Assuming that they are in the same time zones, you would

Convert the 12:50pm into 12:50am by adding 12 hours

Now just add the time from 12:50 to 2:05, which is 1 hour and 15 minutes

All together it equals 13 hours and 15 minutes.

4 0
8 months ago
Read 2 more answers
Divide £72 cm in the ratio 2:3:1
PilotLPTM [1.2K]
2:3:1....added = 6

2/6(72) = 144/6 = 24
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6 0
3 years ago
Anita invested $6000, some at 5% and the rest at 6%. If the yearly income is $337.50, what is the amount invested at each rate?
Pepsi [2]

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5

Multiplying both sides by 100 we get:

5x+6(6000-x)=33750

5x+36000-6x=33750

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-x=-2250

\therefore x=2250

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6 0
2 years ago
10. Jan purchased 140 shares of stock in the ABC Company at a price of $18.75 per share. During the
andre [41]

\bold{\huge{\orange{\underline{ Solution }}}}

\bold{\underline{ Given :- }}

  • <u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
  • <u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>

\bold{\underline{ To \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>

\bold{\underline{ Let's \: Begin :- }}

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

Cost of 1 share of ABC company = $18.75

<u>Therefore</u><u>, </u>

Cost of 140 shares purchased by Jan in the ABC company

\sf{ = 140 × 18.75 }

\sf{ = 2625\: dollars }

<u>Now</u><u>, </u>

For next 3 days, the value of share declined

\sf{ = (1 + 1.75 + 1.50)dollars }

\sf{ = 4.25 \: dollars }

<u>Therefore</u><u>, </u>

The value of shares after 3 days will be

\bold{ = }{\bold{\frac{2625 - 4.25}{ 140}}}

\bold{ = }{\bold{\frac{ 2620.75}{ 140}}}

\bold{\red{ = 18.75\: dollars}}

Hence, The value of share after 3 days will be $18.75 .

5 0
2 years ago
Writing lan's car can go 180 miles on 5 gallons of gas. During a drive last weekend, lan used
MrRissso [65]

Answer:

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If we have the distance, we divide by 36 instead to find how many gallons of gas he used.

Step-by-step explanation:

180/5=36 miles per gallon

8 gallonsx36 miles per gallon=288 miles

pls mark brainliest

6 0
2 years ago
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