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docker41 [41]
3 years ago
9

*The length of the shorter altitude and the shorter side of a parallelogram are 9cm and 82 cm. The length of a longer diagonal i

s 15 cm. What is the area of this parallelogram?

Mathematics
1 answer:
Alja [10]3 years ago
6 0

Refer to the image attached.

Given: Altitude AC = 9 cm, Diagonal AD = 15 cm, side AB = 82 cm.

To find: Area of parallelogram

Solution:

Since, area of parallelogram = base \times height

= BD \times AC

We have to determine the base BD.

Consider the triangle ABC,

by Pythagoras theorem,

(AB)^2 = (BC)^2 + (AC)^2

(82)^2 = (BC)^2 + (9)^2

6724-81= (BC)^2

BC = 81.5 cm

Now, Consider the triangle ACD,

by Pythagoras theorem,

(AD)^2 = (AC)^2 + (CD)^2

(15)^2 = (9)^2 + (CD)^2

225-81= (CD)^2

CD = 12 cm

Now, base BD = BC + CD

= 81.5+12

= 93.5 cm

Area of parallelogram = BD \times AC

= 93.5 x 9

= 841.5 square centimeters.

Therefore, the area of parallelogram is 841.5 square centimeters.

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