Which are composite or prime 9 , 2 , 15 , 21

2 answers:

5 0

A composite number is a number that has more than 2 factors.
A prime number is a number who only have 2 factors (1, and itself)
Factors:-

9 = 1, 3, 9 = composite
2 = 1, 2 = prime
15 = 1, 3, 5, 15 = composite
21 = 1, 3, 7, 21 = composite

So, the prime #'s in this set are 2. The composite #'s in this set are 9, 15, and 21.

Hope I helped ya!!

Georgia [21]3 years ago

5 0

A Prime Number can be divided evenly only by 1 or itself. It alsp must be a whole number greater than 1. Therefore, 9, 15, and 21 are composite and 2 is a prime.

You might be interested in

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.046.0 and

Gala2k [10]

Answer:

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10

Step-by-step explanation:

The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.

The formula of probability if given by:

f(x)=

$\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b } \atop {0}; \ x \ otherwise } \right.$

In this exercise a= 46.0 and b= 56.0

The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:

$\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1$

7 0

3 years ago

Virty [35]

$P\approx0.90$

1) The first thing we need to do is to find the total number of visitors. This is going to be our Sample Space

31+26+2=31+28=59 Visitors altogether

2) The next thing to do is to find the favorable event. Note that we can see that 26 people purchased only one costume.

3) The final and last step is to find the probability, so we can write out the following:

$P=\frac{26}{59}=0.8965\approx0.90$

Thus, this is the answer: 0.90

4 0

1 year ago

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

the probability we get one volleyball player is $\dfrac{24}{46}=\dfrac{12}{23};$
the probability we get another basketball player is $\dfrac{22}{45}$ (only 45 athletes left).