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3 years ago

Which are composite or prime 9 , 2 , 15 , 21

2 answers:

5 0

A composite number is a number that has more than 2 factors.
A prime number is a number who only have 2 factors (1, and itself)
Factors:-

9 = 1, 3, 9 = composite
2 = 1, 2 = prime
15 = 1, 3, 5, 15 = composite
21 = 1, 3, 7, 21 = composite

So, the prime #'s in this set are 2. The composite #'s in this set are 9, 15, and 21.

Hope I helped ya!!

Georgia [21]3 years ago

5 0

A Prime Number can be divided evenly only by 1 or itself. It alsp must be a whole number greater than 1. Therefore, 9, 15, and 21 are composite and 2 is a prime.

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What is 10 1/3 + 7/9 =

Effectus [21]

Is about 11.1111hope that helped

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Step-by-step explanation:

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NO LINKS!!! 14. Consider the table

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Answer:

(a) rate of change = 8

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Range: 0 ≤ y ≤ 16

Explanation:

Looks like a inverse variation sequence.

Inverse Variation formula: y = k(x)

Take two points: (1, 8), (2, 16)

Find the value of k which is constant also considered as rate of change.

Insert values:

8 = k(1)

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2 years ago

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Answer:

he gets 4.33 dollars back

Step-by-step explanation:

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3 years ago

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68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 7.5, \sigma = 1.1$