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Eva8 [605]
3 years ago
13

Which are composite or prime 9 , 2 , 15 , 21

Mathematics
2 answers:
Luda [366]3 years ago
5 0
A composite number is a number that has more than 2 factors.
A prime number is a number who only have 2 factors (1, and itself)
Factors:-

9 = 1, 3, 9 = composite
2 = 1, 2 = prime
15 = 1, 3, 5, 15 = composite
21 = 1, 3, 7, 21 = composite


So, the prime #'s  in this set are 2. The composite #'s in this set are 9, 15, and 21.

Hope I helped ya!! 
Georgia [21]3 years ago
5 0
A Prime Number can be divided evenly only by 1 or itself. It alsp must be a whole number greater than 1. Therefore, 9, 15, and 21 are composite and 2 is a prime.
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16x^2 + 10x — 27 = -6x + 5<br><br> What are the solutions to this equation?
dexar [7]

Answer:

x=1 or x=−2

Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

16x2+16x−32=0

Step 2: Factor left side of equation.

16(x−1)(x+2)=0

Step 3: Set factors equal to 0.

x−1=0 or x+2=0

x=1 or x=−2

4 0
3 years ago
Given the parent function
lozanna [386]

Answer:

Option c is right.

Step-by-step explanation:

Given is a parabola y =x^2

From that transformation is done to get parabola as

y =(0.2x)^2

We find that instead of x here we use 0.2x

i.e. New x = 5 times old x

Hence there is a horizontal expansion of scale factor 5.

We can check with any point also

When y =4, x=2 in the parent graph

But when y =4 , we have x = 10 in the new graph

i.e. there is a horizontal expansion of scale factor 5.

7 0
3 years ago
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For the Best Brain:<br><br> fun question:<br> how do I solve y = 10x + 2 when x equals 3
allsm [11]
You would plug in 3 for x, which gives you y = 10(3) + 2, and then you would use PEMDAS, which means you multiply 10 with 3 and then add two which is 32. Therefore y would equal 32. :D :D
5 0
3 years ago
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coffee worth 90 cents per pound is mixed with coffee worth 60 cents per pound ro produce a twenty pound blend worth 72 cents per
Evgesh-ka [11]
90x+60y=72
60y=-90x+72
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then create a graph using this formula.

Hope this helps!

8 0
3 years ago
Chose all the values of x that are not in the domain of this rational function. Picture attached, 15 points and I'll give Brainl
pogonyaev

Answer:

All of them.

Step-by-step explanation:

For rational functions, the domain is all real numbers <em>except</em> for the zeros of the denominator.

Therefore, to find the x-values that are not in the domain, we need to solve for the zeros of the denominator. Therefore, set the denominator to zero:

x(x-1)(x^2-4)=0

Zero Product Property:

x\neq 0\text{ or }x-1\neq 0\text{ or }x^2-4\neq 0

Solve for the x in each of the three equations. The first one is already solved. Thus:

x-1\neq 0 \text{ or }x^2-4\neq 0\\x\neq 1\text{ or }x^2\neq 4\\x\neq 1 \text{ or }x\neq\pm 2

Thus, the values that <em>cannot</em> be in the domain of the rational function is:

x=-2,0,1,2

Click all the options.

6 0
3 years ago
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