Answer:
-60-14x
Step-by-step explanation:
Distribute the 3: -3(20+5x)+x => 20(-3)+3(-5x)+x => -60 -15x+x
Simplify: -60-15x+x => -60-14x
Step-by-step explanation:
⇒12)It is an arithmetic sequence.
d=2-1=3-2=4-3=1
a(n) = a +(n-1)d
a(n) = 1+(n-1)1
The next three terms:
a(6) = 1+(6-1)1=6
a(7) = 1+(7-1)1=7
a(8) = 1+(8-1)1=8
⇒13)It is an arithmetic sequence.
d=0-3=-3-0=-6+3=-3
a(n) = a +(n-1)d
a(n) = 3+(n-1)-3
The next three terms:
a(5) = 3+(5-1)-3=-9
a(6) = 3+(6-1)-3=-12
a(7) = 3+(7-1)-3=-15
⇒14)It is <u>not </u>an arithmetic sequence.
⇒15) a(50) = 10 +(50-1)5
=<u>255</u>
<u>I hope this helps</u>
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Answer: Option D
Step-by-step explanation:
By definition if we have a function F (x) and perform a transformation of the form

Then it is true that:
If c is negative the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the right
If c is positive, the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the left.
Note that in this case the transformation is:

Then
and 
Therefore the graph of G(x) will be equal to the graph of F(x) displaced horizontally <em>9 units to the left</em>
The answer is the option D.
Answer: (5+√2) and (3+√2)
Step-by-step explanation: Let (5+√2) and (3+√2) be two irrational numbers
Difference = (5+√2) - (3+√2)
Difference = 2
2 is a rational number
Answer:
The probability that the message will be wrong when decoded is 0.05792
Step-by-step explanation:
Consider the provided information.
To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.
We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.
The digit transmitted is incorrectly received with probability p = 0.2
The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8
We want the probability that the message will be wrong when decoded.
This can be written as:

Hence, the probability that the message will be wrong when decoded is 0.05792