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3 years ago

Find 4 times 213 useing expanded form

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

4 x 213 = 4 x (200 + 10 + 3) = 852

12345 [234]3 years ago

5 0

213 + 213 + 213 + 213 = 852

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13. Find the surface area of the triangular prism shown.

Soloha48 [4]

Answer:

49.84

Step-by-step explanation:

Hope it helped!

6 0

2 years ago

Read 2 more answers

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh

Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = $-0.02x^{2} +0.8x+3$

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = $-0.02x^{2} +0.8x+3$

Y(x) = $-0.02(10)^{2} +0.8(10)+3$

Y(x) = $-0.02(100)} +8+3$

Y(x) = $-2 +8+3$

Y(x) = $9$

Therefore, Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D. 9 ft is correct

6 0

3 years ago

PLS HELP ANSWER ASAP MARK BRAINLEIST

Alenkinab [10]

X is always dependant to Y. so that should answer the 1st one. the 2nd looks to be around 17-18. 17.5 maybe. and the 3rd is yes cause he does not go to the pool so it isnt any cost.

3 0

3 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$