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4 years ago

WILL GIVE BRAINLY!!!!PLEASE HELP!!!!

Mathematics

1 answer:

olasank [31]4 years ago

6 0

Answer:

None of the above

Step-by-step explanation:

A graph of the function f(x) = 4x- 8 is straight line passing through (0,-8) on y axis and (2,0) on x axis.

Thus, we observe that both Domain and Range belongs R (real no.), but none of above options states that.

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Convert to % 1) 1/2 2) 1/4 3) 1/3 4) 3/10 5) 6.5/10

inna [77]

Answer:

1) 50%

2) 25%

3) 33.33 %

4) 30%

5) 65%

6 0

3 years ago

PLEASE HELP

notsponge [240]

Answer:

(a)

x cubed is

=x^3=x3

5 times the cube of x is

=5x^3=5x3

4 times x is

=4x=4x

the quotient of 4 times x and 3 is

=\frac{4x}{3}=34x

so,

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is

=5x^3-\frac{4x}{3}=5x3−34x ..........Answer

(b)

5 times cube of x is

=5x^3=5x3

5 times cube of x divided by 4 times x is

=\frac{5x^3}{4x}=4x5x3 ..........Answer

(c)

difference of 5 times x cube and 4 is

=5x^3 -4=5x3−4

so,

the quotient of the difference of 5 times x cube and 4 and x is

=\frac{5x^3-4}{x}=x5x3−4 ...........Answer

(d)

difference of 5 times x and 4 is

=5x-4=5x−4

so,

the cube of the difference of 5 times x and 4 is is

=(5x-4)^3=(5x−4)3 ............Answer

5 0

3 years ago

Which algebraic expression represents “the quotient of a number and thirty"?

UNO [17]

Answer:

a/30

Step-by-step explanation:

quotient means divide

a/30 because "a number" was first in the expression

3 0

3 years ago

Read 2 more answers

Sam worked on his science fair project for 1/4 hour on Friday and 1/2 hour on Saturday. What are four common denominators for th

tatyana61 [14]

4, 8, 12, 16 because they are all multiples of 4 and 2

5 0

3 years ago

Read 2 more answers

Solve for x <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7Bx%7D%20%20%2B%20%5Cfrac%7Bb%7D%7Bc%7D%20%3D%20%20%5Cfr

larisa86 [58]

Easy
make denomenators the same

Step 1
multiply both sidesby (x)(c)(b+c)
(a)(c)(b+c)+(b)(x)(b+c)=(a)(x)(c)

Step 2
distribute
acb+ac²+xb²+bxc=axc

Step 3
minus (acb+ac²) from both sides
xb²+bxc=axc-acb-ac²

Step 4
minus axc from both sides
xb²+bxc-axc=-acb-ac²

Step 5
undistribute x
x(b²+bc-ac)=-acb-ac²

Step 6
divide both sides by (b²+bc-ac)
$x= \frac{-acb-ac^2}{b^2+bc-ac} =\frac{acb+ac^2}{ac-b^2-bc}$

4 0

4 years ago