An attacker is preparing to perform what Application attack when the target vulnerabilities include headers and payloads of specific application protocols.
<h3>What Is an Application Attack?</h3>
An application attack is known to be a type of system attack which is made up of cyber criminals that is said to have access to any unauthorized points.
Note that this kind of Attackers are the ones that start by looking at the application layer, and then looking for any kind of application vulnerabilities that is found within the code.
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Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
Answer:
14
Explanation: The reason why is because adding a negative is pretty much subtracting by 2. 9-2=7. Then multiply 7 by 2 like add 7 to 7 and you get 14.
Answer:
Normalization of storage is a typical method of storing the floating point number by shifting the decimal after the first figure of the number such as 1101.101 is normalized to 1.101101x23.
If the number that is in hovering point representation has 1 sign bit, 3-bit exponent with a 4-bit significant:
whenever the storage is normalized, then the biggest positive floating spot number in 2`s and the complement notation is 0.11112 x 23 = 111.12 =7.5
If the storage is returned to normal, then the minimum positive floating point number is 0.12 x 2-4 =0.000012 =1/32 = 0.03125.
Explanation:
Whenever the floating figure is keyed into the computer memory, then the first bit will be the sign bit, the next 8 bits are for exponent and 23 bits are used for storing significand. The array of exponents is from -127 to 128. While Exponent 127 stands for 0 and positive figures can be represented by values bigger than 127. The biggest floating point number will be represented as 0.111111.... 1111x 211111111
