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lilavasa [31]
3 years ago
12

A 0.145 kg baseball pitched at 43.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. if the c

ontact time between bat and ball is 2.00 multiplied by 10-3 s, calculate the average force between the ball and bat during contact
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0
- If the contact time between bat and ball is 3.00 10-3 s, calculate the average force between the ball and bat during contact. ... now that we have dp we divide it by 3 x 10^-3 s. ... therefore the average force ( or impulse) between the ball and the bat during contact is 12000 N.
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Step-by-step explanation:

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2 years ago
Jill is factoring the expression 13XY -52y. Her work is shown below
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Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

3 0
3 years ago
Help no explanation just answers plz, theres no multi choice
maxonik [38]

Answer:

A b or c

Step-by-step explanation:

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2 years ago
Evaluate loook at the pic
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17

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2 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
2 years ago
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