A.) R(20) = -10(20)^2 + 800(20) = -10(400) + 16000 = -4000 + 16000 = $12,000
R(25) = -10(25)^2 + 800(25) = -10(625) + 20000 = -6250 + 20000 = $13,750
R(30) = -10(30)^2 + 800(30) = -10(900) + 24000 = -9000 + 24000 = $15,000
b.) For maximum revenue, dR/dp = 0
dR/dp = -20p + 800 = 0
20p = 800
p = 40
Therefore, the maximum revenue will be recorded when the price is set at $40.
Answer:
y have 3K
xD
Step-by-step explanation:
Answer:
The only multiples of 3 between 20 and 30 are 21, 24, and 27. Only 27 satisfies the condition that it is 3 times the sum of its digits.
Step-by-step explanation:
