For problem one she starts off earning 10.24 dollars per hour. She receives a raise of 1.60 dollars. So first you have to add both 10.24 and 1.60 together to find out how much more she is payed. 10.24+1.60=12.04. She works 22.25 hours. It would take forever to add 12.04 22 and a quarter times so you multiply them. 12.04*22.25=267.89. So she would earn 267.89 dollars from working 22.25 hours.
For problem two you would start off by dividing 3/4 (the amount of pizza) by 5 (the five people) because when you do this it will give you the equal amount of pizza that each person can have. You get 0.15 which is equal to 3/20. So each person will get 3/20 of the 3/4 of the pizza that are left. (To simplify it the answer is 3/20) you can check your work by doing 3*5 which is 15. Make this the numerator and it’s 15/20. 15/20=3/4.
For the third problem you start off by putting aside the .25 of an ounce. Take the 3 ounces and multiply it by the cost per ounce 3.56. 3*3.56=10.68. Now that you have figured out how much 3 ounces cost out that aside. Now for the .25 of an ounce. Since .25 goes into one four times you do 3.56/4. It’s 0.89. This is how much it costs per .25 of an ounce. After that you add 10.68+0.89. It’s 11.57. To finish the problem you have to subtract 11.57 from 20 dollars. 20.00-11.57=8.43. The teacher receives $8.43 in change.
Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so
P=2(L+W)=2(80+50+170+50)
P=2(350)=700m
Under A straight line basis which is a method of computing depreciation and amortization by dividing the difference between an asset's cost and its expected salvage value by the number of years it is expected to be used. Also known as straight line depreciation or straight line amortization, this is the simplest depreciation method. But instead of that find The rate of depreciation
100/5 years=20% depreciation rate per year
Total cost 250×50=12,500
Salvage value 40×50=2,000
Subtract the salvage value from the total cost of televisions
12,500−2,000=10,500
In the first year the depreciation is
10,500×0.2=2,100
Book value
12,500−2,100=10,400
In the second year the depreciation is
10,500×0.2=2,100
Book value
10,400−2,100=8,300
In the third year the depreciation is
10500×0.2=2100
Book value
8300-2100=6200
the book value for all of the televisions at the end of the third year is 6200
Answer: The Answer to this is
The line representing the number of screws required to assemble x of Bookcase B is steeper than the line representing the number of screws required to assemble x of Bookcase A because there are more screws used in each Bookcase B than in each Bookcase A.
Step-by-step explanation:
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