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aksik [14]
4 years ago
13

Ellen separated the area of a poster into four equal sections.The perimeter of the poster is 120 inches.What is the area of one

section of the poster?
Mathematics
1 answer:
Black_prince [1.1K]4 years ago
8 0
Clarify the shape of the poster and possible lines for the sections.
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IF YOU HELP ME WITH THIS I WILL HELP YOU WITH SOMETHING IF YOU NEED HELP!! State if each triangle is a right triangle. The trian
juin [17]

Answer:

6 - yup        7 - nope

Step-by-step explanation:

If the triangle satisfies the pythagoreon theorem, then it is a right triangle

so 6 is a yeah

then for 7, the hypotunese always is greater than the legs in a right triangle, so 7 is no

4 0
3 years ago
If the diameter of the circle is 6 cm, find its circumference. [Use 3.14 for π.] A) 18.84 cm B) 25.12 cm C) 37.68 cm D) 50.24 cm
agasfer [191]
Circumference = π * d

π=3.14
diameter = 6

3.14 * 6 = 18.84.
The answer is A.

Hope this helped☺☺
7 0
3 years ago
Read 2 more answers
A cone and its dimensions are shown in the diagram. Which measurement is closest to the volume of the cone in cubic inches?
Diano4ka-milaya [45]
20 Cubic Inches^3.

Explanation:

The volume of a cone is Pi*R^2*H*1/3

We know the height, but we are given the diameter instead of radius. So divide 5.625 by 2. You get 2.8125.

Plug everything into the formula.

Pi*2.8125^2*7.5*1/3

(The ^2 means squared, or to the second power)

You get a number close to 20. Since we don’t know Pi, and we are not given a substitute for Pi, we make the answer in terms of Pi.

20 Cubic Inches^3.

Also, people who don’t know the answers to questions shouldn’t just put a random answer for the points. It’s unfair.


3 0
3 years ago
Jason wants to plant 66 carrot seeds and 44 onion bulbs. He would like to plant them so
dexar [7]

The greatest number of plants he can have in each row is 22

He would have 3 rows of carrots

He would have 2 rows of onions

<h3>Greatest Common Factor</h3>

From the question, we are to determine the greatest number of plants he can have in each row

From the given information,

Jason wants to plant 66 carrot seeds and 44 onion bulbs

The greatest number of plants he can have in each row is the greatest common factor of 66 and 44

Factors of 66: 1, 2, 3, 6, 11, 22, 33, and 66

Factors of 44:  1, 2, 4, 11, 22 and 44

The greatest common factor of 66 and 44 is 22

Thus,

The greatest number of plants he can have in each row is 22

He would have 66/22 rows of carrots

66/22 = 3

Thus,

He would have 3 rows of carrots

He would have 44/22 rows of onions

44/22 = 2

Hence, he would have 2 rows of onions

Learn more on Greatest Common Factors here: brainly.com/question/5535901

#SPJ1

3 0
2 years ago
An oil painting has a price of
Debora [2.8K]

Answer:

i think it $3.20

Step-by-step explanation:i think you got to check it in caculator

3 0
4 years ago
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