All categories

3 years ago

Composition of matter which depends on temperature.

Biology

2 answers:

Eduardwww [97]3 years ago

8 0

I don't know the answer options, but it would probably either be phase of matter or physical change.

Inessa [10]3 years ago

8 0

sorry but its phase of matter

You might be interested in

This can contribute to desert formation:

Tatiana [17]

Answer:

Explanation:

Due to the erosion of soils, no trees to protect the ground from drying out.

3 0

3 years ago

Read 2 more answers

In cats, curled ears result from an allele, Cu, that is dominant over an allele cu, for normal ears. Black color results from an

just olya [345]

Answer:

Explanation:

Cross : ggCuCu X GGcucu --------Parents

F1 progeny : GgCucu

Two of the F1 cats mate :

Cross : GgCucu X GgCucu

Gametes :

Gg X Gg = GG, Gg, Gg, gg

Cucu X Cucu = CuCu, Cucu, Cucu, cucu

1/4 GG X 1/4 CuCu = 1/16 GGCuCu (black - curled ears)

1/4 GG X 2/4 Cucu = 2/16 GGCucu (black - curled ears)

1/4 GG X 1/4 cucu = 1/16 GGcucu (black - normal ears)

2/4 Gg X 1/4 CuCu = 2/16 GgCuCu (black - curled ears)

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 1/4 cucu = 2/16 Ggcucu (black - normal ears)

1/4 gg X 1/4 CuCu = 1/16 ggCuCu (gray - curled ears)

1/4 gg X 2/4 Cucu = 2/16 ggCucu (gray - curled ears)

1/4 gg X 1/4 cucu = 1/16 ggcucu (gray - normal ears)

Answer : (i). 9/16 black cats, curled ears; 3/16 black cats, normal ears; 3/16 gray cats, curled ears; and 1/16 gray cats, normal ears.

An F1 cat mates with a stray cat that is gray and possesses normal ears :

Cross : GgCucu X ggcucu

Gametes :

Gg X gg = Gg, Gg, gg, gg

Cucu X cucu = Cucu, Cucu, cucu, cucu

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 2/4 cucu = 4/16 Ggcucu (black - normal ears)

2/4 gg X 2/4 Cucu = 4/16 ggCucu (gray - curled ears)

2/4 gg X 2/4 cucu = 4/16 ggcucu (gray - normal ears)

Answer : (i). 1/4 black cats, curled ears; 1/4 black cats, normal ears; 1/4 gray cats, curled ears; 1/4 gray cats, normal ears.

6 0

4 years ago

DNA is made up of pairs of nitrogenous bases. Which of the following

Leokris [45]

I don't know the real answer because you didn't attach the choices, but Adenine (A) is always paired with Thymine(T) and Guanine (G) is always paired with Cytosine (C).

8 0

3 years ago

In rabbits, black fur (B) is dominant to white fur (b). A purebred black furred male is bred with a female that had the recessiv

ValentinkaMS [17]

Answer:

All the offsprings will be black-furred (Bb)

Explanation:

This question involves a single gene coding for fur length in rabbits. The allele for black fur (B) is dominant to the allele for white fur (b). This means that a rabbit heterozygous for this gene (Bb) will have a black fur.

According to this question, a purebred black furred male (BB) is bred with a female that had the recessive white fur (bb). The parents will produce gametes as follows:

BB - B only

bb - b only

Using these gametes in a punnet square (see attached image), the genotypic proportion of the produced offsprings is as follows:

Bb, Bb, Bb, Bb

All Bb (heterozygous) means that all of the offsprings will be black-furred.

8 0

3 years ago

Nuclear energy comes from what?

zmey [24]

Answer:

Uranium

Explanation:

8 0

3 years ago