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3 years ago

If the value of 2x^3 is 2, then what is the value of x?

Mathematics

2 answers:

ratelena [41]3 years ago

8 0

Well start at 0,1,2,3, etc. and plug in the numbers until you get you answer of 2!

nata0808 [166]3 years ago

3 0

I THINK the value of x = 1

Divide both sides by 2:

2x^3/2 = 2/2

x^3 = 1

Take the cube root:

x = 1^1/3

x = 1

If someone can confirm this, that would be greatly appreciated. Thank you :)

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Someone help me with this question please.

frosja888 [35]

Answer:

Andre scored 14 points.

Equation: x = 14

Step-by-step explanation:

Let the number of points Andre scored be x.

Diego's points = x-9

Noah's points = (x-9) × 2

= 2x-18

Now, you know the exact value of Noah's points which is 10.

2x-18 = 10

Isolate the 2x.

2x = 10+18

= 28

x = 28÷2

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Which statement describes how to determine if a relation given in a table is a function?

const2013 [10]

Answer: B

Step-by-step explanation: A function is a relation in which each input value is paired to exactly one output value.

Technically, if you had the same input value twice and the same output value corresponded to each of those, it would still be a function because you are just repeating what you have twice.

However, most teachers want to think of it as each input value must have exactly one corresponding value to be a function.

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3 years ago

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A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th

Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

$\tan\theta=\frac{Perpendicular}{base}$

Here, $\theta=11.1^{\circ}$ ,Perpendicular AB = 4000

$\tan\theta=\frac{AB}{BC}$

$\tan 11.1^{\circ} =\frac{4000}{BC}$

Solving for BC, we get,

$BC=\frac{4000}{\tan 11.1^{\circ} }$

$BC=\frac{4000}{0.196}$ (approx)

$BC=20408.16$ (approx)

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

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3 years ago

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Answer:

Step-by-step explanation:

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ziro4ka [17]

The equation of a parabola is:
$y = ax {}^{2} + bx + c$
If a>0, then the parabola opens up;
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3 years ago