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patriot [66]
4 years ago
8

A new youth activity center is being built in oak valley. the perimeter of the rectangular playing field is 332 yards. the lengt

h of the field is 5 yards less than double the width. what are the dimensions of the playing​ field?
Mathematics
2 answers:
allsm [11]4 years ago
8 0

In this question, it is given that

A new youth activity center is being built in oak valley. the perimeter of the rectangular playing field is 332 yards. the length of the field is 5 yards less than double the width.

Let the width is x yards . And length is 5 yards less than double the width, so length is (2x-5) yards  .

Perimeter is the sum of all sides, that is

x+2x-5+x+2x-5 = 332
\\
6x-10 = 332
\\  6x = 342
\\
x = 57 yards

So the width is 57 yards and length is

2x-5 = 2*57-5 = 109 yards

DaniilM [7]4 years ago
6 0

<em>Answer:</em> The width is 56 yards and the length is 110 yards.

<em>Step-by-step explanation: </em>I don't know how to get the answer but when I got it wrong, it gave me the correct answer and its 56 yards and 110 yards.

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