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o-na [289]
3 years ago
15

There are several different models that represent compounds. One type of model is shown.What type of model is shown?a structural

formulaa chemical formulaa space-filling modela ball-and-stick model

Physics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

D.

Explanation:

Finger [1]3 years ago
3 0

Answer: Option (d) is the correct answer.

Explanation:

A model in which a spheres resemble ball are attached with the sticks is known as a ball-and-stick model.

In this models, balls represents the atoms present whereas sticks represent the bonds between the toms.

Thus, we can conclude that out of the given options, type of model is shown is a ball-and-stick model.

You might be interested in
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
Your friend comes across a good deal to purchase a gold ring. She asks you for advice and for you to test the ring. The ring has
Luden [163]

Answer:

She is not getting a good deal.

Explanation:

The equation that relates heat with mass, specific heat and temperature change of an object is Q=mc\Delta T.

Always convert temperature to Kelvin, although in our case it's not necessary because the \Delta T will be the same, and we will leave the mass in grams because we will be getting J/g^{\circ}C units for specific heat, which we can compare to the one given for gold.

We then calculate the specific heat of the object in question:

c=\frac{Q}{m\Delta T}=\frac{94.8J}{(4.54g)(47.5^{\circ}C-23^{\circ}C)}=0.8523 J/g^{\circ}C

Which shows it's not gold.

5 0
3 years ago
A cheetah can run from 0 to 70 mph in 2.2 seconds. what is speed in m/s
sattari [20]
70 mph

= 70 * 1600 m/h

= <span>112000 m/h

-> 112000 m/h

= 112000 /3600 m/s

= 31.111... m/s

= <u>31 m/s (2s.f)</u></span>
7 0
3 years ago
With enough time, would an ice pop melt on a cool autumn day? Explain.
Ber [7]
Yes, an autumn day isn’t cold enough to keep an a ice pop at freezing temperatures.
3 0
3 years ago
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