A fire because you feed it wood, it lives longer but if you give it a drink, water, then it dies.
Answer:
![-6.25\cdot 10^7 J](https://tex.z-dn.net/?f=-6.25%5Ccdot%2010%5E7%20J)
Explanation:
The gravitational potential at a point on the Earth surface is given by:
![U=-\frac{GM}{R^2}](https://tex.z-dn.net/?f=U%3D-%5Cfrac%7BGM%7D%7BR%5E2%7D)
where
G=6.67×10^-11Nm^2kg^-2 is the gravitational constant
M=5.98×10^24kg is the Earth's mass
R=6.38×10^6 m is the Earth's radius
Substituting the numbers into the equation, we find
![U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J](https://tex.z-dn.net/?f=U%3D-%5Cfrac%7B%286.67%5Ccdot%2010%5E%7B-11%7D%29%285.98%5Ccdot%2010%5E%7B24%7D%29%7D%7B%286.38%5Ccdot%2010%5E6%29%7D%3D-6.25%5Ccdot%2010%5E7%20J)
Explanation:
Band of stability for atomic nuclei refer to a narrow region in the graph of number of neutrons to the number of protons for stable nuclei. It is the band of nuclei stability.
We know that radioactive elements achieve stability be ejecting nucleons( neutrons and protons). The regions( combination of number of neutrons and protons) in which the nucleus is most is called band of stability.
Answer:
A.) 355 m/s
B.) 0.71 m
C.) 500Hz
Explanation:
Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s
a.) What is the speed of the sound waves relative to you?
Since the car is moving away from the observer, the relative velocity will be:
Relative velocity = 340 + 15
Relative velocity = 355 m/s
b.) What is the wavelength of the sound waves at your location?
Using the wave speed formula
V = frequency × wavelength
Make wavelength the subject of formula.
Wavelength = Velocity / frequency
Wavelength = 355/500
Wavelength = 0.71 m
c.) What frequency do you detect?
Fo = Fs ( C + V ) / ( C + v )
Fo = Fs
That is, the frequency of the observer will be equal to the frequency of the source.
Therefore, Fo = 500Hz