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VMariaS [17]
3 years ago
9

The speed of the water at the tap of lower storey is more than that in the upper storey,why?

Physics
2 answers:
masha68 [24]3 years ago
5 0

With lower, the mechanics have to work harder to give water. Resulting in faster spray. But with upper, they do not have to work as hard which makes it not work as fast.

fiasKO [112]3 years ago
3 0
This is your answer

Please mark me as a brainliest

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The weight of a body of certain mass becomes zero in space.why?write with reasons​
Anvisha [2.4K]

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

7 0
3 years ago
Which part of earths surface has the greatest rotational speed
Anni [7]
Every point on the surface must have the same rotational speed.
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3 years ago
A spring with a spring constant value of 125 N/m is compressed 12.2 cm by pushing on it with a 215 g block. When the block is re
allsm [11]

Answer:

v = 2.94 m/s

Explanation:

When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.

Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.

Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means

(1/2)kx^2 = (1/2)mv^2

kx^2 = mv^2

v^2 = (kx^2)/m

v = sqrt((kx^2)/m)

v = x * sqrt(k/m)

v = 0.122 * sqrt(125/0.215)        <--- units converted to m and kg

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3 0
2 years ago
What is an ellipse?
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Answer:

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6 0
3 years ago
A physics major is working to pay her college tuition by performing in a traveling carnival. She rides a motorcycle inside a hol
il63 [147K]

Answer:

v = 12.1 m/s

Explanation:

  • When at the top of the circle, there are two forces acting on the combined mass of the rider and the motorcycle.
  • These are the force of gravity (downward) and the normal force, which is directed from the surface away from it, perpendicular to the surface.
  • In this case, as the motorcycle runs in the interior of the circle, at the top point this force is completely vertical, and is also downward.
  • Since the motorcycle is moving in a vertical circle, there must be a force, keeping the object moving around a circle.
  • This force is the centripetal force, aims towards the center of the circle, and is just the net force aiming in this direction at any point.
  • At the top point, this force is just the sum of the normal force and the weight of the mass of the rider and the motorcycle combined, as follows (we take the direction towards the center as positive):

       F_{c} = N + m*g (1)

  • Now, we know that the centripetal force is related with the tangential speed at this point and the radius of the circle as follows:

       F_{c} = m*\frac{v^{2}}{r} (2)

  • Since the normal force takes any value as needed to make (1) equal to (2),  if the speed diminishes, it will be needed less force to keep the equality valid.
  • In the limit, when the motorcyvle tires barely touch the surface, this normal force becomes zero.
  • In this condition, from (1) and (2), we can find the minimum possible value of  the speed that still keeps the motorcycle touching the surface, as follows:
  • v_{min} =\sqrt{r*g} =\sqrt{15.0m*9.8m/s2} = 12.1 m/s (3)
6 0
3 years ago
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