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bija089 [108]
4 years ago
5

Which steps are important when designing and conducting a scientific experiment

Physics
1 answer:
artcher [175]4 years ago
8 0
Having your space clean. have on close toed shoes. have your hair pulled back into a ponytail. keep ur work space clean. wear gloves and goggles. do not have on droopy clothes. follow the steps on the board and double check them. 
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Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne
slega [8]

Answer:

\epsilon = 2.96 \times 10^{-11} \ V

Explanation:

given,

magnetic field strength =  1.40 ✕ 10⁻³ T

frequency of oscillation = 60 Hz

diameter of RBC = 7.5 μm

EMF = ?

\epsilon = NBA\omega

\epsilon = NB(\pi\ r^2)\ (2\pi f)

\epsilon = NB(\pi\ (\dfrac{d}{2})^2)\ (2\pi f)

\epsilon = (1)\ 1.4 \times 10^{-3}(\pi\ (\dfrac{7.5 \times 10^{-6}}{2})^2)\ (2\pi\times 60)

\epsilon = 2.96 \times 10^{-11} \ V

maximum emf that can generate around the perimeter of the cell \epsilon = 2.96 \times 10^{-11} \ V

5 0
3 years ago
If a bowling ball rolls 12 meters in 2.2 seconds what is the speed ?
Evgesh-ka [11]

Answer:19000

Explanation:I don’t know

8 0
4 years ago
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3 0
3 years ago
Read 2 more answers
Learning Goal: To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circ
andreev551 [17]

Answer:

v = 15.8 m/s

Explanation:

Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement.  So the variation of mechanical energy is equal to the work of the fictional force

    W_{fr} = ΔEm = Em_{f} -Em₀

Let's write the mechanical energy at each point

Initial

    Em₀ = Ke = ½ k x²

Final

   Em_{f} = K + U = ½ m v² + mg y

Let's use Hooke's law to find compression

    F = - k x

    x = -F / k

    x = 4400/1100

    x = - 4 m

Let's write the energy equation

    fr d = ½ m v² + mgy - ½ k x²

Let's clear the speed

   v² = (fr d + ½ kx² - mg y) 2 / m

   v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50)   2/60.0

   v² = (160 + 8800 - 1470) / 30

   v = √ (229.66)

   v = 15.8 m/s

5 0
4 years ago
Read 2 more answers
What is the specific heat of the masses in this experiment? Infer the substance the masses are made of and explain your inferenc
Liono4ka [1.6K]

The metal whose specific heat capacity is close to the obtained value is aluminum.

<h3>What is specific heat capacity</h3>

The specific heat capacity of an object is the heat required to raise a unit mass of the substance by 1 kelvin.

Q= mc\Delta \theta

where;

  • c is the specific heat capacity
  • Δθ is change in temperature

Let the mass of the water = 50 g

mass of the metal for this first trial = 50 g

The heat gained by the water is calculated as follows

Q = 50 \times 4.184 \times 8.4\\\\Q = 1757.28 \ J

Specific heat capacity of the metal for the first trial is calculated as follows;

Heat gained by water = Heat lost by metal

C = \frac{Q}{m\Delta T} = \frac{1757.28}{50\times 8.4} = 4.184 \ J/g^oC

Specific heat capacity of the metal for the second trial;

mass of metal = 200 - mass of water = 150 g

C_2 = \frac{1757.28}{150 \times 15.2} = 0.77 \ J/g^oC

Specific heat capacity of the metal for the third trial;

C_3 = \frac{1757.28}{250 \times 20.8} = 0.34\ J/g^oC

Specific heat capacity of the metal for the fourth trial;

C_4 = \frac{1757.28}{350 \times 25.4} = 0.19\ J/g^oC

Specific heat capacity of the metal for the fifth trial;

C_5 = \frac{1757.28}{450 \times 29.6} = 0.13\ J/g^oC

Average specific heat capacity

C = \frac{4.184 + 0.77 + 0.34+ 0.19 + 0.13 }{5} = 1.12 \ J/g^oC = 1120 J/kg^oC

The metal whose specific heat capacity is close to the above value is aluminum.

Learn more about specific heat capacity here: brainly.com/question/16559442

8 0
2 years ago
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