tectonic plates rubbing against each other.
Explanation:
Work done is given by the product of force and displacement.
Case 1,
1. A boy lifts a 2-newton box 0.8 meters.
W = 2 N × 0.8 m = 1.6 J
2. A boy lifts a 5-newton box 0.8 meters.
W = 5 N × 0.8 m = 4 J
3. A boy lifts a 8-newton box 0.2 meters.
W = 8 N × 0.2 m = 1.6 J
4. A boy lifts a 10-newton box 0.2 meters.
W = 10 N × 0.2 m = 2 J
Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.
Fréquence of 20,000hz is called ULTRASOUND
Answer:
The center of mass move with the velocity of -3.487 m/s.
Explanation:
Given values of block A.
Mass of block A, (M1) = 4 kg
Speed of block A, (V1) = 2 m/s
Given values of block B.
Mass of block B, (M2) = 8.4 kg
Speed of block B, (V2) = -6.1 m/s
Below is the formula to find the velocity of center of mass.




Answer:
0.694 m
Explanation:
Case 1 : When only mass of 2.82 kg is hanged from spring
m = mass hanged from the spring = 2.82 kg
x = stretch caused in the spring = 0.331 m
k = spring constant
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
k (0.331) = (2.82) (9.8)
k = 83.5 N/m
Case 2 : When both masses are hanged from spring
m = mass hanged from the spring = 3.09 + 2.82 = 5.91 kg
x = stretch caused in the spring = ?
k = spring constant = 83.5 N/m
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
(83.5) x = (5.91) (9.8)
x = 0.694 m