Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
The quotient of the synthetic division is x^3 + 3x^2 + 4
<h3>How to determine the quotient?</h3>
The bottom row of synthetic division given as:
1 3 0 4 0
The last digit represents the remainder, while the other represents the quotient.
So, we have:
Quotient = 1 3 0 4
Introduce the variables
Quotient = 1x^3 + 3x^2 + 0x + 4
Evaluate
Quotient = x^3 + 3x^2 + 4
Hence, the quotient of the synthetic division is x^3 + 3x^2 + 4
Read more about synthetic division at:
brainly.com/question/18788426
#SPJ1
Answer:
6 days
Step-by-step explanation:
pay 60 = -60
Let d = the number of days
30d - 60 = sister
20d = me
Equation:
30d - 60 = 20d Move 30 to the other side
-30d -30d
-60 = 20d - 30d Combine liked terms
-60 = -10d
-10 -10 Divide
d = 6
