Answer:
a. 1620-x^2
b. x=810
c. Maximum value revenue=$656,100
Step-by-step explanation:
(a) Total revenue from sale of x thousand candy bars
P(x)=162 - x/10
Price of a candy bar=p(x)/100 in dollars
1000 candy bars will be sold for
=1000×p(x)/100
=10*p(x)
x thousand candy bars will be
Revenue=price × quantity
=10p(x)*x
=10(162-x/10) * x
=10( 1620-x/10) * x
=1620-x * x
=1620x-x^2
R(x)=1620x-x^2
(b) Value of x that leads to maximum revenue
R(x)=1620x-x^2
R'(x)=1620-2x
If R'(x)=0
Then,
1620-2x=0
1620=2x
Divide both sides by 2
810=x
x=810
(C) find the maximum revenue
R(x)=1620x-x^2
R(810)=1620x-x^2
=1620(810)-810^2
=1,312,200-656,100
=$656,100
Answer:
The answer is intersect
Step-by-step explanation:
Answer:
y=5x-9
Step-by-step explanation:
Answer:
n=65th term
Step-by-step explanation:
AP:3,15,27,39......
From the AP
a=3
a+d=15
a+2d=27
3+d=15 (1)
3+2d=27 (2)
Subtract (1) from (2)
We have,
2d-d=27-15
d=12
54th term=a+(n-1)d
=3+(54-1)12
=3+(53)12
=3+636
=639
The term is 132 more than the 54th term
132+54th term
=132+639
=771
Find the term
771=a+(n-1)d
771=3+(n-1)12
771-3=12n-12
768=12n-12
768+12=12n
780=12n
n=780/12
=65
n=12
The term which is 132 more than the 54th term is the 65th term
