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bagirrra123 [75]
3 years ago
7

Solve the equation for part a

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0
I cannot see the entire problem
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Find the equilibrium point for the pair of demand and supply functions. Here q represents the
olya-2409 [2.1K]

The equilibrium point for the pair of demand and supply function is 100

We have been two linear function, one is linear supply function and other is linear demand function.

In general , linear supply function is given as:

                            Qs = x + yP

                       Where , Qs = quantity supplied

                                        x = quantity

                                        P = price

And linear demand function is given is :

                             Qd = x + yP

                      Where , Qs = quantity supplied

                                        x = quantity

                                        P = price

According to the question,

                   Linear supply function is q = 300 + 5x

          And  linear demand function is q = 4800 – 40x

To find the equilibrium point we will put two quantities equal, that is,

                                 Qs = Qd

                      300 + 5x = 4800 – 40x

                        5x + 40x = 4800 – 300

                          45x = 4500

                             x =  100

Hence the equilibrium point is 100

Learn more about equilibrium point here : brainly.com/question/1915798

#SPJ9

4 0
1 year ago
Describe how you would find how much grass seed is needed to cover a triangular plot of land
Papessa [141]

Answer: it the area of it

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
16 3/7 −4 3/4 <br> subtract this fraction correctly and i will mark you brainliest
Ivan

Answer:

the nswer is 11.6785714286

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can someone pls help me ?
Firlakuza [10]
-4 is the correct answer. -24= -4/6
8 0
3 years ago
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