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Snowcat [4.5K]
3 years ago
13

How many lines of symmetry does a regular polygon with 22 sides have

Mathematics
1 answer:
masya89 [10]3 years ago
8 0
There are 22 lines the same amount of sides

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Alice purchased paint in a bucket with a radius of 9 in. and a height of 9.5 in. The paint cost $0.09 per in3.
PilotLPTM [1.2K]
217.46 hope this helps
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4 years ago
Dallison cooked a 5-pound roast for supper.What is estimated mass in grams?
Kay [80]
1 pound=16ouncees
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8 0
3 years ago
write a quadratic function in vertex form whose graph has the vertex (1,0) and passes through point (2,-17)
kobusy [5.1K]

Answer:

\displaystyle f(x) = -17(x-1)^2

Step-by-step explanation:

We want to write a quadratic function in vertex form whose vertex is (1, 0) and passes through the point (2, -17).

Recall that vertex form is given by:

\displaystyle f(x) = a(x-h)^2 + k

Where (<em>h</em>, <em>k</em>) is the vertex and <em>a</em> is the leading coefficient.

Since our vertex is at (1, 0), <em>h</em> = 1 and <em>k</em> = 0:

\displaystyle f(x) = a(x-1)^2

It passes through the point (2, -17). Hence, when <em>x</em> = 2, <em>y</em> = -17:

\displaystyle (-17) = a((2)-1)^2

Solve for <em>a: </em>

<em />\displaystyle a = -17<em />

<em />

In conclusion, our quadratic function in vertex form is:

\displaystyle f(x) = -17(x-1)^2

7 0
3 years ago
Express your answer as a polynomial in standard form.
Musya8 [376]

Answer:

f(g(x)) = 6x^2+6x+11

Step-by-step explanation:

f(g(x)) = 2(3x^2+3x+7) - 3\\f(g(x)) = 6x^2 + 6x + 14 - 3\\f(g(x)) = 6x^2+6x+11

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3 years ago
Linear or nonlinear x-3y=10
irina1246 [14]
Non linear because based on the statement is shown is linear equations in two variables ok ........
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4 years ago
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