Which question do you need help with?
Answer:
yes
Step-by-step explanation:
Any number that can be written in p/q from is a rational number
Probability of finding no defective bulb
=95/100*94/99....86/91
=95!/(85!) / (100!/90!)
= 110983/190120
=>
Probability of finding at least one defective bulb
=1-110983/190120
= 79137/190120
= 0.41625 (to 5 decimal places)
; 134
a:8
n:44
3.6
3.6
P,ob.Z);Jlty : 1 - P(:
<z<-
[ - ]]p(-2.98 ' z ' 2.98)]
[ -]p(z ' 2.98) - p(z ' -2.98)]
[ - E0.9986 - 0.0014]
=0.0028
53.778 is the answer. I hope this helps and have a good day!
