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3 years ago

In which quadrant, if any, is the point left parenthesis negative 104 comma 3 right parenthesis(−104,3) located?

Mathematics

2 answers:

DerKrebs [107]3 years ago

8 0

I think it's in quadrant 2

Diano4ka-milaya [45]3 years ago

5 0

-104 is to the left. Then, 3 is up. So it would be the top left quadrant, or quadrant number 2. I hope this helps!

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

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2 years ago

Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3

Veronika [31]

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Simplify 8.5x*10000 to 85000x
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This is for number 10

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3 years ago

I just need to know the answer to B.

sleet_krkn [62]

Answer:

24%

Step-by-step explanation:

45 + 37 + 52 + 94 + 72 = 300

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7 0

3 years ago

In which​ quadrant, if​ any, is the point left parenthesis negative 104 comma 3 right parenthesis(−104,3) ​located?

In which quadrant, if any, is the point left parenthesis negative 104 comma 3 right parenthesis(−104,3) located?