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GrogVix [38]
3 years ago
7

In which​ quadrant, if​ any, is the point left parenthesis negative 104 comma 3 right parenthesis(−104,3) ​located?

Mathematics
2 answers:
DerKrebs [107]3 years ago
8 0
I think it's in quadrant 2
Diano4ka-milaya [45]3 years ago
5 0
-104 is to the left. Then, 3 is up. So it would be the top left quadrant, or quadrant number 2. I hope this helps!
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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)
andrezito [222]

Answer:

a) \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325

b) The lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

Step-by-step explanation:

a) To simplify the expression \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right) you must:

Apply Difference of Two Squares Formula: \left(a+b\right)\left(a-b\right)=a^2-b^2

a=18,\:b=\tan \left(x\right)

\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)

324-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Apply the Pythagorean Identity 1+\tan ^2\left(x\right)=\sec ^2\left(x\right)

From the Pythagorean Identity, we know that 1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Therefore,

324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325

b) According with the below graph, the lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

3 0
3 years ago
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Andreas93 [3]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3
Veronika [31]
Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
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5 0
3 years ago
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Ira Lisetskai [31]
This is for number 10

6 0
3 years ago
I just need to know the answer to B.
sleet_krkn [62]

Answer:

24%

Step-by-step explanation:

45 + 37 + 52 + 94 + 72 = 300

72/300 = 0.24 x 100

= 24%

7 0
3 years ago
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