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GrogVix [38]
2 years ago
7

In which​ quadrant, if​ any, is the point left parenthesis negative 104 comma 3 right parenthesis(−104,3) ​located?

Mathematics
2 answers:
DerKrebs [107]2 years ago
8 0
I think it's in quadrant 2
Diano4ka-milaya [45]2 years ago
5 0
-104 is to the left. Then, 3 is up. So it would be the top left quadrant, or quadrant number 2. I hope this helps!
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] You are scheduled to receive $20,000 in two years. When you receive it, you will invest it for six more years at 8.4 percent p
Alex Ar [27]

Answer:

32449.3

Step-by-step explanation:

use the formula A = P(1+r / 100)^t

20000 × (1+ (8.4 / 100))^6

=32449.3

6 0
3 years ago
F(b)-f(a)
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8 0
2 years ago
Can you help me with 12-3(x+1)=30
inysia [295]
Greetings!

12-3(x+1)=30
Distribute the Parenthesis.
12-3x-3=30
Combine like terms.
9-3x=30
Add -9 to both sides.
(15-3x)+(-9)=(30)+(-9)
-3x=21
Divide both sides by -3.
(-3x)/-3=(21)/-3
The Answer Is:
x=-7

Hope this helps.
-Benjamin
7 0
3 years ago
43/645= I need the to show the work
Licemer1 [7]
I'm guessing you need 43/645 simplified:

First, we need to find the greatest common factor (GCF) of the numerator (43) and the denominator (645). To do so, we list all the factors of each number and find the common ones.

Factors of 43: 1, 43
Factors of 645: 1, 3, 5, 15, 43, 129, 215, 645

Out of the listed factors for each number, which numbers are common between the two? The common factors are 1 and 43. Since we are looking for the GREATEST common factor, which number out of 1 and 43 is the greatest? The GCF is 43.

Second, we can now divide the numerator (43) and the denominator (645) by the GCF we recently found which was 43. 

43 \div 43 = 1 \\ 645 \div 43 = 15

Third, our new simplified fraction is 1/15. We collected our new numerator and denominator.

Answer in fraction form: \fbox {1/15}
Answer in decimal form: \fbox {0.0667}
4 0
2 years ago
0) Select all ordered pairs that correspond to input-output pairs of the function y = -8x + 4.
patriot [66]
A, B, and D are the correct answers.
7 0
3 years ago
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