Answer:
141.56 N.
Explanation:
Data given:
Weight of the box= 200.2 N
Angle with the horizontal= 37.1°
Solution;
Gravitational force on the box, = weight of the box
= 200.2 N
Component of gravitational force along plane = ( ∅ )
= W * (sin∅)
= (200.1) * sin (37.1°)
= 141.56 N
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is
Explanation:
From the question we are told that
The mass of the block is
The initial speed of the block before entering the rough section is
The time taken is t = 0.5 s
The speed with which the block leaves the rough section is
Generally from kinematic equation
=>
=>
=>
Generally the magnitude of the average frictional force is mathematically represented as
=>
=>
The negative sign show that the force is acting in the opposite direction to the direction of motion of the block
